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In a reaction, 2A to Products, the concentration of A decreases from 0.5 mol L^(-1) to 0.4 mol L^(-1) in 10 minutes. Calculate the rate during this interval . |
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Answer» Solution :AVERAGE RATE `=-(1)/(2) (DELTA[A])/(Delta t)= -(1)/(2)([A]_(2)-[A]_(1))/(t_(2)-t_(1))` `= -(1)/(2) xx (0.4M-0.5M)/("10 minutes")= -(1)/(2) xx (-0.1M)/("10 minutes")=5xx10^(-3)" mole minutes"^(-1)`. |
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