Saved Bookmarks
| 1. |
In a reaction ,2Ato products ,the concentration of A decreases from 0.5 mol L^(-1) to 0.4 mol L^(1) in 10 minutes.Calculate the rate during this interval. |
|
Answer» SOLUTION :Reaction 2A `to` Product, Time =10 minute `THEREFORE Deltat=10 "minute:-0 "minute" =10 "minute"` `Rate=-(1)/(2)(DELTA[A])/(Deltat)` `=-((0.4-0.5)mol L^(-1))/(2XX10 m)` `+(0.1)/(2xx10),ol L^(-1) m^(-1)` `=5.0 xx10^(-3) mol L^(-1) m^(-1)` |
|