1.

In a reaction ,A + B toProduct , rate is doubled when the concentration of B is doubled ,and rate increases by a factor of 8 when the concentrations of both the reactants (A and B) are doubled , rate law for the reaction can be written as

Answer»

RATE = `K[A] [B]^(2)`
Rate = k `[A]^(2) [B]^(2)`
Rate = k [A] [B]
Rate= `k [A]^(2) [B]`

Solution :
That MEANS order of reaction with respect to B is 1 and w.r.t. A is 2
Hence , Rate = `k [A]^(2) [B]^(1)`


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