1.

In a reaction A toproducts, when start is made from 8.0times10^(-2)M of A, half-life is found to be 120minute. For the initial concentration 4.0times10^(-2)M, the half-life of the reaction becomes 240 minutes. The order of the reaction is :

Answer»

zero
one
two
0.5

Solution :`((t_((1)/(2)))_(1))/((t_((1)/(2)))_(2))=((a_(2))/(a_(1)))^(n-1)`, `(120)/(140)=((4times10^(-2))/(8times10^(-2)))^(n-1) , n=2`


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