1.

In a reaction, between A and B, the initial rate of reaction (r_(0)) was measured for different initial concentrations of A and B as given below : What is the order of reaction with respect to A and B ?

Answer»

SOLUTION :`r_(0)= k[A]^(ALPHA)[B]^(beta)`
`(r_(0))_(1)=k XX 5.07 xx 10^(-5)=(0.20)^(alpha) (0.30)^(beta) ""…(i)`
`(r_(0))_(2)= k xx 5.07 xx 10^(-5)= (0.20)^(alpha) (0.10)^(beta)"" …(ii)`
`(r_(0))_(3)=k xx 1.43xx10^(-4)=(0.40)^(alpha) (0.05)^(beta) ""...(iii)`
Dividing (i) by (ii)
`(r_(0))_(1)//(r_(0))_(2)=1=(0.30//0.10)^(beta)=(3)^(beta)`
`therefore beta=0`
Dividing (iii) by (ii)
`(r_(0))_(3)//(r_(0))_(2)=(7.16)/(5.07)=(0.40//0.20)^(alpha) (0.05//0.10)^(beta)`
or `1.412=2^(alpha)((1)/(2))^(beta)=2^(alpha) ""[because beta=0]`
or `LOG 1.412=alpha log 2`
or `alpha=0.1523//0.3010=0.5`
Thus, ORDER w.r.t. A = 0.5, order w.r.t. B = 0.


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