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In a reaction between A and B, the initial rate of reaction was measured for different intial concentrations of A and B as given below : {:(A//"mol L"^(1),,,0.20,,,0.20,,,0.40),(B//"mol L"^(-1),,,0.30,,,0.10,,,0.05),(r_(0)//"mol L"^(-1)s^(-1),,,5.07xx10^(-5),,,5.07xx10^(-5),,,7.16xx10^(-5)):} Whatis the order of reaction with respect to Aand B ? |
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Answer» SOLUTION :`r_(0)=[A]^(alpha)[B]^(beta)` `(r_(0))_(1)=5.07xx10^(-5)=(0.20)^(alpha)(0.30)^(beta)""...(i)` `(r_(0))_(2)=5.07xx10^(-5)=(0.20)^(alpha)(0.10)^(beta)""...(ii)` `(r_(0))_(3)=7.16xx10^(-5)=(0.40)^(alpha)(0.05)^(beta)""...(iii)` `((r_(0))_(1))/((r_(0))_(2))=1=((0.30)/(0.10))^(beta)=(3)^(beta):.beta=0` `((r_(0))_(3))/((r_(0))_(2))=(7.16)/(5.07)=((0.40)/(0.20))^(alpha)((0.05)/(0.10))^(beta)" or "1.412=2^(alpha)((1)/(2))^(beta)=2^(alpha)( :.beta=0)` `log1.412=alphalog2"or"alpha=0.1523//0.3010=0.5.` `("or directly "1.412=sqrt(2)=2^(1//2):.2^(alpha)=2^(1//2)" or "alpha=1//2)` THUS, order w.r.t. A = 0.5, orderw.r.t. B = 0 |
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