InterviewSolution
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InterviewSolution
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In a reaction carried out at `500 K, 0.001%` of the total number of colliisons are effective. The energy of activation of the reaction is approximatelyA. `15.8 kcal mol^(-1)`B. `11.5 kcal mol^(-1)`C. `12.8 kcal mol^(-1)`D. zero |
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Answer» Correct Answer - B The fraction of molecules having energy equal to or greater than `E_(a)` is : `x = (n)/(N) = e^(-E_(a)//RT) (x = (n)/(N) = 0.001% = (0.001)/(100) = 10^(-5))` `:. log x = (-E_(a))/(2.3 xx RT) = (R = 2 cal mol^(-1) K^(-1), T = 500 K)` `log 10^(-5) = (-E_(a))/(2.3 xx 2 xx 500)` `E_(a) = 11.5 xx 103 cal mol^(-1) = 11.5 kcal mol^(-1)` |
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