1.

In a reaction, if half of the double bond is broken and two new bonds are formed, this is a case of

Answer»

Elimination
Addition
Displacement
Rearrangement

Solution :e.g. `CH_2=CH_2+Br_2 to undersetunderset(Br)(|)CH_2-undersetunderset(Br)(|)CH_2`
HALF of the DOUBLE bond is broken. Its MEANS `PI` bond is broken while sigma bond is retained also two new C-Br bonds are formed


Discussion

No Comment Found