InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
In a refrigerator, heat from inside at `277 K` is transferred to a room at `300K`. What is the cofficient of performance of the refrigerator. How many joule of heat will be deliverd to the room for each joule of electric energy consumed ideally? |
|
Answer» Correct Answer - `12.04 ; 13.04J` Here, `T_(2)= 277K` `T_(1)= 300K, COP=? Q_(1)=?` `W=1J` `COP= (Q_(2))/W=(T_(2))/(T_(1)-T_(2))` `COP=(273)/(300-277)= (273)/(23)=12,04` Again, as `COP= (Q_(2))/W=(Q_(2))/(1J)= 12.4` `Q_(2)= 12.04J` `Q_(1)=Q_(2)+W= 12.04+1= 13.04J` |
|