1.

In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in the region. The path of the particle will be a.......

Answer»

Circle
Helix
Ellipse
Straight LINE

Solution :The charged particle experience a force `F_(e)`in this region and after some time it experiences force `vecF_(m)=q(VECV xx vecb)` with VELOCITY `vecv`.

Here `vecv || vecB, therefore F_(m) =qvBsin0^(@), therefore vecF_(m) =0`
So if the charge is positive then it is mov opposite to electric field and if it is negative move in straight line in the DIRECTION of elect: field.


Discussion

No Comment Found

Related InterviewSolutions