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In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in the region. The path of the particle will be a....... |
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Answer» Circle ![]() Here `vecv || vecB, therefore F_(m) =qvBsin0^(@), therefore vecF_(m) =0` So if the charge is positive then it is mov opposite to electric field and if it is negative move in straight line in the DIRECTION of elect: field. |
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