In a reversible adiabatic change Delta Sis – InterviewSolution

1.	In a reversible adiabatic change Delta Sis
Answer» equal to `NR LN V_2//V_1` 0 equal to `C_V DT` infinity Solution : For adiabatic changes q = 0, therefore `DELTA S = 0` as`Delta S`=q/T.

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