1.

In a reversible reaction, the enthalpy change and the activation energy in the forward direction are respectively -xkJmol and y kJ mol ^(-1) . Therefore , the energy of activation in the backward direction is ........

Answer»

`(y-x) "KJ MOL"^(-1)`
`(x+y)J mol^(-1)`
`(x-y)kJ mol^(-1)`
`(x+y)xx10^3J mol^(-1)`

SOLUTION :
`(x+y)"kJ mol"^(-1)`
`(x+y) xx10^3"J mol"^(-1)`


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