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In a rhombus PQRS, if PQ = 3x – 7 and QR = x + 3 find PS. |
Answer» PQ = QR [Sides of a rhombus] 3x – 7 = x + 3 3x – x = 3 + 7 2x = 10 x = \(\frac{10}{2}\) x = 5 PQ = 3x – 7 = 3 × 5 – 7 =15 – 7 PQ = 8cm ∴ SP = 8 |
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