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In a Rutherford's scattering experiment when a projectile of chargez Z_(1)and mass M_(1)approaches a target nucleus of Z_(2)and mass M_(2) the distance of closest approach is r_(0). The energy of the projectile is........ |
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Answer» directly PROPORTIONAL to `Z_(1), Z_(2)` `(1)/(2)mv^(2)=((Z_(1)E)(Z_(2)e))/(4pi epsi_(0)r_(0))=(Z_(1)Z_(2)e^(2))/(4pi epsi_(0)r_(0))` So the energy of projectile is proportional to `Z_(1),Z_(2)` |
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