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In a sample of 40 vehicles, 18 are red, 6 are trucks, of which 2 are red. Suppose that a randomly selected vehicle is red. What is the probability it is a truck? |
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Answer» One vehicle is selected from 40 vehicles. Let event A: The selected vehicle is red. There are total of 18 red vehicles. ∴ P(A) =\(\frac {^{18}C_1}{^{40}C_1} = \frac {18} {40} = \frac {9}{20}\) Let event B: The selected vehicle is a truck. There are total of 6 trucks. Since 2 trucks are red, they are common between A and B. ∴ P(A ∩ B) = \(\frac {^{2}C_1}{^{40}C_1} = \frac {2} {40} = \frac {1}{20}\) ∴ Probability that the selected vehicle is a truck under the condition that it is red = P(B/A) = \(\frac {(PA∩B)}{P(A)}\) = \(\frac {\frac{1}{20}}{\frac{9}{20}}\) = 1/9. |
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