1.

In a satellite if the time of revolution is `T`, then kinetic energy is proportional toA. `1/T`B. `1/(T^(2))`C. `1/(T^(3))`D. `T^(2//3)`

Answer» Correct Answer - B
`K=1/2mv^(2)=1/2m omega^(2) R^(2)=1/2m((2pi)/T)^(2) R^(2)`
`=(2pi^(2)mR^(2))/(T^(2))`
`K prop 1/(T^(2))`


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