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In a saturated solution of the sparingly soluble strong electrolyte AgIO_(3) (Molecular mass = 283) the equilibrium which sets in is AgIO_(3_(s)) hArr Ag_((aq))^(-) + IO_(3_(aq))^(-) If the solubility product constant K_(sp) of AgIO_(3) at a given temperature is 1.0 xx 10^(-8), what is the mass of AgIO_(3) contained in 100 ml of its saturated solution |
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Answer» `28.3 xx 10^(-2) g` `K_(sp) = [AG^(+)] [IO_(3)^(-)]` `1.0 xx 10^(-8) = s^(2)` `s = 10^(-4)` mol/litre `= (10^(-4) xx 283)/(1000) xx 100 = 283 xx 10^(-5) = 2.83 xx 10^(-3)` g/100 ML. |
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