In a school, 45% of the students play football, 30% play volleyball an

1.	In a school, 45% of the students play football, 30% play volleyball and 15% both. If a student is selected at random, then the probability that he plays football or volleyball is:
Answer» 3/5 Given that, 45% play football; that is, P(F) = 45/100 = 9/20 30% play VOLLEY ball; that is, P(V) = 30/100 = 6/20 And, 15% play both volleyball and football; that is, P(F And V) = 15/100 = 3/20 Now, we have to FIND the probability that 1 STUDENT plays football or volley ball; that we have to find, P(F or V) We know that, P(F Or V) = P(F) + P(V) - P(F And V) = 9/20 + 6/20 - 3/20 = 12/20 = 3/5. Hence, the required probability 3/5.

In a school, 45% of the students play football, 30% play volleyball and 15% both. If a student is selected at random, then the probability that he plays football or volleyball is:

Answer»

3/5

Given that, 45% play football; that is, P(F) = 45/100 = 9/20
30% play VOLLEY ball; that is, P(V) = 30/100 = 6/20
And, 15% play both volleyball and football; that is, P(F And V) = 15/100 = 3/20
Now, we have to FIND the probability that 1 STUDENT plays football or volley ball;
that we have to find, P(F or V)
We know that, P(F Or V) = P(F) + P(V) - P(F And V)
= 9/20 + 6/20 - 3/20 = 12/20 = 3/5.
Hence, the required probability 3/5.

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In a school, 45% of the students play football, 30% play volleyball and 15% both. If a student is selected at random, then the probability that he plays football or volleyball is:

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