In a series `C-R` circuit shown in figureure, the applied voltage is `10 V` and the voltage across capacitor is found to`8 V`. The voltage across `R`, and the phase difference between current and the applied voltage will respectively be .A. `6V, tan^-1(4/3)`B. `3V,tan^-1(3/4)`C. `6V,tan^-1(3/4)`D. none of these

In a series `C-R` circuit shown in figureure, the applied voltage is `

1.	In a series `C-R` circuit shown in figureure, the applied voltage is `10 V` and the voltage across capacitor is found to`8 V`. The voltage across `R`, and the phase difference between current and the applied voltage will respectively be .A. `6V, tan^-1(4/3)`B. `3V,tan^-1(3/4)`C. `6V,tan^-1(3/4)`D. none of these
Answer» Correct Answer - A `V_R=sqrt(V^2-V_C^2)=sqrt((10)^2-(8)^2)=6V` `tanphi=X_C/X_R=V_C/V_R=8/6=4/3`

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