1.

In a series LCR circuit , and alternating emf (v) and current (i) are given by the equationv=v_(0) sin omegat, i=i_(0)sin (omegat+(pi)/(3)). The average power dissipated in the circuit over a cycle of AC is

Answer»

<P>`(v_(0)i_(0))/(2)`
`(v_(0)i_(0))/(4)`
`sqrt(3)/(2)v_(0)i_(0)`
Zero

Solution :`phi` = PHASE difference betweeen V and `I=(pi)/(3)`
`P_(ave)=V_(rms)I_(rms)cosphi`
`=((V_(0))/(sqrt(2)))((I_(0))/(sqrt(2)))COS((pi)/(3))=(V_(0)I_(0))/(2)xx(1)/(2)=(V_(0)I_(0))/(4)`


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