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In a series LCR circuit R = 200 Omegaand the voltage and the frequency of the main supply is 220 V and 50 Hz respectively. On taking out the capacitance from the circuit the current lags behind the voltage by 30°. On taking out the inductor from the circuit the current leads the voltage by 30°. The power dissipated in the LCR circuit is |
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Answer» 305 W As on taking capacitor out of CIRCUIT CURRENT LAGS behind VOLTAGE by 30° and on taking inductor out current leads by 30°, so we conclude that `X_(C) = X_(L)` and it is a resonance situation. `THEREFORE I_(rms) = (220V)/(200 Omega) = 1.1A` and power dissipated,`=V_(rms).I_(rms) = 220V xx 1.1 A = 242 W` |
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