1.

In a series LCR circuit , the potential drop across L, C and R respectively are 40 V , 120V and 60V . Then the source voltage is

Answer»

220 V
160 V
180 V
100 V

Solution :`V=SQRT(V_(R)^(2)+(V_(C)-V_(L))^(2))`
`=sqrt(60^(2)+(120-40)^(2))`
`V=100` volt


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