1.

In a series resonant LCR circuit, the voltage across R is 100 volts and R=1 k Omega with C = 2 uF. The resonant frequency w is 200 rad s^(-1). At resonance the voltage across L is

Answer»

`2.5 xx 10^(-2)` V
40 V
250 V
`4 xx 10^(-3)` V

SOLUTION :Here V = 100 V, R = `1k OMEGA = 1000 Omega, C = 2muF = 2 xx 10^(-6) F` and `omega = 200 rad s^(-1)`
At RESONANCE `I = V/R = 100/(1000) = 0.1 A`
`therefore` Voltage across L = voltage across `C = IX_( C) = (0.1)/(2 xx 10^(-6) xx 200) = 250 V`


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