In A Simultaneous Throw Of Pair Of Dice. Find The Probability Of Gett

1.	In A Simultaneous Throw Of Pair Of Dice. Find The Probability Of Getting The Total More Than 7?
Answer» <P>Here n(S) = (6 x 6) = 36 Let E = event of getting a total more than 7 = {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)} THEREFORE,P(E) = n(E)/n(S) = 15/36 = 5/12. Here n(S) = (6 x 6) = 36 Let E = event of getting a total more than 7 = {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)} Therefore,P(E) = n(E)/n(S) = 15/36 = 5/12.

In A Simultaneous Throw Of Pair Of Dice. Find The Probability Of Getting The Total More Than 7?

Answer»

<P>Here n(S) = (6 x 6) = 36

Let E = event of getting a total more than 7

= {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}

THEREFORE,P(E) = n(E)/n(S) = 15/36 = 5/12.

Here n(S) = (6 x 6) = 36

Let E = event of getting a total more than 7

= {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}

Therefore,P(E) = n(E)/n(S) = 15/36 = 5/12.