Saved Bookmarks
| 1. |
In a single state transistor amplifier, when by 10muA and collector current by 1mA. If collector load R_(C )=2kOmega and R_(L)=10kOmega, Calculate : (i) Current Gain (ii) Input impedance, (iii) Effective ac load, (iv) Voltage gain and (v) Power gain. |
|
Answer» <P> Solution :(i) Current Gain `beta=(Deltai_(c))/(Deltai_(b))beta=(Deltai_(c))/(Deltai_(b))=(1mA)/(10muA)=100`(ii) INPUT impedance `R_(i)=(DeltaV_("BE"))/(Deltai_(b))=(0.02)/(10muA)=2000Omega=2kOmega` (iii) Effective (a.c) LOAD `R_(AC)==R_(C)||R_(L))` `therefore R_(AC)=(2xx10)/(2+10)=1.66kOmega` (iv) Voltage gain, `A_(v)=betaxx(R_(AC))/(R_("in"))=(100xx1.66)/(2)=83` (v) `"Power gain, "A_(p)="Current gain"xx"Voltage gain"` `=100xx83=8300` |
|