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In a single toss of a fair die, what are the odds against the event that number 3 or 4 turns up? |
Answer» When a fair die is tossed, the sample space is S = {1, 2, 3, 4, 5, 6} ∴ n(S) = 6 Let event A: 3 or 4 turns up. ∴ A = {3, 4} ∴ n(A) = 2 ∴ P(A) = \(\frac {n(A)}{n(S)} = \frac {2} {6} = \frac {1}{3}\) P(A’) = 1 - P(A) = 1 - 1/3 = 2/3 ∴ Odds against the event A are P(A’) : P(A) = 2/3 : 1/3 = 2:1 |
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