1.

In a single toss of a fair die, what are the odds against the event that number 3 or 4 turns up?

Answer»

When a fair die is tossed, the sample space is 

S = {1, 2, 3, 4, 5, 6} 

∴ n(S) = 6 

Let event A: 3 or 4 turns up. 

∴ A = {3, 4} 

∴ n(A) = 2

 ∴ P(A) = \(\frac {n(A)}{n(S)} = \frac {2} {6} = \frac {1}{3}\)

P(A’) = 1 - P(A) = 1 - 1/3 = 2/3

∴ Odds against the event A are P(A’) : P(A)

= 2/3 : 1/3

= 2:1



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