1.

In a solution , 0.02 M acetic acid is 4% dissociation . The [OH^(-)] in the solution is

Answer»

`8 xx 10^(-4)`
`2xx10^(-14)`
`8xx10^(10)`
`1.25 xx 10^(-11)`

Solution :`[H^(+)]=sqrt(alpha^(2)C^(2))=sqrt((0.02)^(2)*(0.04)^(2))=8xx10^(-4)`
`[H^(+)][OH^(-)]=10^(-14)`
`:. [OH^(-)]=(10^(-14))/(8xx10^(-4))=1.25xx10^(-11)M`


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