1.

In a solution of 7.8 gm benzene C_(6)H_(6) and 46.0 gm toluene (C_(6)H_(5)CH_(3)), the mole fraction of benzene in this solution is

Answer»

`1//6`
`1//5`
`1//2`
`1//3`

SOLUTION :Mole fraction at `C_(6)H_(6)=((7.8)/(78))/((7.8)/(78)+(46)/(92))=(1)/(6)`.


Discussion

No Comment Found