Saved Bookmarks
| 1. |
In a standard YDSE setup if the screen is kept tilted as shown, find the distance OA if first maximum is formed at A. Wavelength of light emitted by source is lambda |
|
Answer» `(Dlambda SEC theta)/(d+LAMBDA tan theta)`  `OB = y tan theta` `O'B = D-y tan theta` position of 1st maximum above the axis `y = (lambda(O'B))/(d)` `y = (lambda(D - y tan theta))/(d) = (lambda D)/(d) - (lambda y tan theta)/(d)` `y[1+(lambda tan theta)/(d)] = (lambda D)/(d)` `y = (lambda D)/(d+lambda tan theta)` Then position of 1st maximum from centre of SCREEN is OA `Cos theta = (y)/(OA)` `OA = y sec theta` `:.OA = (lambda D sec theta)/(d + lambda tan theta)` |
|