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InterviewSolution
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In a stationary wave pattern that forms as a result of reflection pf waves from an obstacle the ratio of the amplitude at an antinode and a node is `beta = 1.5.` What percentage of the energy passes across the obstacle ? |
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Answer» We know that, `(A_(max))/(A_("min"))=(A_(i)+A_(r))/(A_(i)-A_(r))=(3)/(2)` (given) `2A_(i)+2A_(r)=3A_(i)-3A_(r)` `2A_(r)+3A_(r)=3A_(i)-2A_(i)` `5A_(r)=A_(i)` `(A_(r))/(A_(i))=(1)/(5)` `(l_(r))/(l_(i))=((A_(r))/(A_(i)))^(2)=((1)/(5))^(2)=(1)/(25)` `l_(r)=0.04l_(i)` `because4%` of the incidennt energy is reflected or 96% energy passes across the obstacle. |
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