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In a thermal reactor the mean lifetime of one generation of thermal neutrons is tau=0.10 s. Assuming the multiplication constant to be equal to k=1.010, find : (a) how many times the number of neutrons in the reactor, and consequently its power, will increase over t=1.0 mi n , (b) the period T of the reactor, i.e., the time period over which its power increases e-fold. |
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Answer» Solution :(a) This number is `K^(n-1)` where `n=` no. of generations in TIME `t=t//T` SUBSTITUTION GIVES `388`. (B) We write `k^(n-1)=E^(((T)/(tau)-1)In k)` or `(T)/(tau)-1=(1)/(In k)` and `T=tau(1+(1)/(In k))=10.15 sec` |
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