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In a thermodynamic process, a system absorbs 2 kilo calorie of heat and at the same time does 500 J of work. What is the change in internal energy of the system: |
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Answer» `-500 J` `therefore dU =dQ-dW` Here `dQ =2000" CAL. "=2000xx4 CDOT 2=8400 J and dW=500 J` `therefore dU =8400 -500=7900 J` THUS, correct choice is (c ). |
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