1.

In a thermodynamic process, a system absorbs 2 kilo calorie of heat and at the same time does 500 J of work. What is the change in internal energy of the system:

Answer»

`-500 J`
500 J
7900 J
8900 J

Solution :Since `DQ=dU+dW`
`therefore dU =dQ-dW`
Here `dQ =2000" CAL. "=2000xx4 CDOT 2=8400 J and dW=500 J`
`therefore dU =8400 -500=7900 J`
THUS, correct choice is (c ).


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