In a thermodynamic process helium gas obeys the law `TP^(2//5)` = constant,If temperature of `2` moles of the gas is raised from `T` to `3T`, thenA. heat given to the gas is `9RT`B. heat given to the is zeroC. increase in internal energy is `6RT`D. work done by the gas is `-6RT`.

In a thermodynamic process helium gas obeys the law `TP^(2//5)` = cons

1.	In a thermodynamic process helium gas obeys the law `TP^(2//5)` = constant,If temperature of `2` moles of the gas is raised from `T` to `3T`, thenA. heat given to the gas is `9RT`B. heat given to the is zeroC. increase in internal energy is `6RT`D. work done by the gas is `-6RT`.
Answer» Correct Answer - B::C::D In adiabatic process `DeltaQ=0` `DeltaU=nc_(v)DeltaT=2((3)/(2)R)(3T-T)=6RT` ltBRgt `DeltaW=-DeltaU=-6RT , DeltaW=-DeltaU=-6RT`

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In a thermodynamic process helium gas obeys the law `TP^(2//5)` = constant,If temperature of `2` moles of the gas is raised from `T` to `3T`, thenA. heat given to the gas is `9RT`B. heat given to the is zeroC. increase in internal energy is `6RT`D. work done by the gas is `-6RT`.

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