1.

In a three-digit number, the hundreds digit is three times the tens digit. The tens digit is three times the ones digit. If the sum of the digits is thirteen, find the number..

Answer»

Answer:

Let the THREE digits be X,y,z such that x is at unit place, y is at TEN and z is HUNDREDTH place.

z = 2y … A

x = 3Y … B

Number = N= 100z + 10y + x

x + y + z = 18 … 1

According to condition:

3y + y + 2y = 18 … 2

From eq 2:

6y = 18

y = 18/6 = 3

y = 3

Using the value of y in eq B:

x = 3 × 3 = 9

x = 9

Using the value of y in eq A:

z = 2 × 3 = 6

z = 6

The number N = (100×6) + (10×3 )+ (1×9) = 600+30+9 = 639

N = 639

The 3-digit number is 639.


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