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In a transistor beta=45, the change in the voltage across 5 kOmega resistor which is connected in collector circuit is 5V. Find the change in base current. |
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Answer» Solution :Change in the COLLECTOR current `DeltaI_(C)=DeltaV//R_(L)` `DeltaI_(C)=(5)/(5xx10^(3))=10^(-3)A=1mA` But `BETA=(DeltaI_(C))/(DeltaI_(B))` `DeltaI_(B)=(DeltaI_(C))/(beta)=(10^(-3))/(45)=0.022mA`. Change in BASE current `(DeltaI_(B))=0.022mA` |
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