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In a transistor (beta = 45) , the voltage across 5kOmega load resistance in collector circuit is 5V. The base current is : |
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Answer» 0.022 mA Now `I_cR_L=5V:.I_c=5/R_L=5/(5XX10^(3))=10^(-3)=1MA` `:.I_b=I_c/45= 10^(-3)/45=0.022 xx10^(-3)A=0.022mA ` |
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