1.

In a transistor (beta = 45) , the voltage across 5kOmega load resistance in collector circuit is 5V. The base current is :

Answer»

0.022 mA
0.978 mA
1.0 mA
2.5 mA

Solution :`beta=I_c/I_b:.I_c/I_b=45`
Now `I_cR_L=5V:.I_c=5/R_L=5/(5XX10^(3))=10^(-3)=1MA`
`:.I_b=I_c/45= 10^(-3)/45=0.022 xx10^(-3)A=0.022mA `


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