In a transistor connected in a common emitter mode, R_o-4kW, R_i=1W,I_c=1muA and I_b =20muA. The voltaged gain is :

In a transistor connected in a common emitter mode, R_o-4kW, R_i=1W,I_

1.	In a transistor connected in a common emitter mode, R_o-4kW, R_i=1W,I_c=1muA and I_b =20muA. The voltaged gain is :
Answer» 100 200 300 400 Solution :VOLTAGE GAIN `A_v=(DeltaI_c)/(DeltaI_b)xxE_a/R_i` `=(1XX10^(-3))/(20xx10^(-6))xx4/1` `=1000/5=200`.

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In a transistor connected in a common emitter mode, R_o-4kW, R_i=1W,I_c=1muA and I_b =20muA. The voltaged gain is :

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