1.

In a transistorconnected in the common base configuartion, alpha=0.95,I_E=1mA.Calculate the value of I_C and I_B.

Answer»

SOLUTION :`ALPHA=(I_C)/(I_E)`
`I_C=alphaI_E=0.95xxI=0.95mA`
`I_E=I_B+I_C`
`:. I_B=I_C-I_E=1-0.95=0.05mA`


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