1.

In a triangle `A B C`, the bisectors of angles `Ba n dC`lies along the lines `x=ya n dy=0.`If `A`is `(1,2)`, then the equation of line `B C`is`2x+y=1`(b) `3x-y=5``x-2y=3`(d) `x+3y=1`A. 2x+y=1B. 3x-y=5C. x-2y=3D. x+3y=1

Answer» Correct Answer - B
The reflections of A in the two angle bisectors will lie on the line BC, So, (2,1) and (1,-2) will lie on BC. The equation of BC will be
`y+2 = ((1+2)/(2-1))(x-1)`
i.e., 3x-y=5


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