1.

In a triangle ABC, if cot""A/2 cot""B/2=c, cot""B/2 cot""C/2=a and cot""C/2 cot""A/2=b, then 1/(s-a)+1/(s-b)+1/(s-c)=

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` 1 `
` 2`
` abc `
` DELTA `

ANSWER :B


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