In a triangle, area is numerically equal to its perimeter. Find area o

1.	In a triangle, area is numerically equal to its perimeter. Find area of it’s incircle.
Answer» <P>The relation between area of a TRIANGLE A, its perimeter P and its inradius r is, $\longrightarrow A=\dfrac{1}{2}Pr$ Given that area is numerically equal to its perimeter. $\longrightarrow A=P$ $\longrightarrow P=\dfrac{1}{2}Pr$ Since perimeter is NON - zero, $\longrightarrow\dfrac{r}{2}=1$ $\longrightarrow r=2$ Hence the area of the incircle is, $\longrightarrow A_r=\pi r^2$ $\longrightarrow\underline{\underline{A_r=4\pi}}$