InterviewSolution
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InterviewSolution
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In a triangle, if the angles `A , B ,a n dC`are in A.P. show that `2cos1/2(A-C)=(a+c)/(sqrt(a^2-a c+c^2))` |
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Answer» Since angles A, B, and C are in A.P., we have `A + C = 2B` But, `A + B + C = 180^(@) " or " 3B = 180^(@) " or " B = 60^(@)` Now, `cos B = (1)/(2) = (a^(2) + c^(2) - b^(2))/(2ac)` or `a^(2) + c^(2) - b^(2) = ac` or `a^(2) - ac + c^(2) = b^(2)` `:. (a + c)/(sqrt(a^(2) - ac + c^(2))) = (a + c)/(b)` `= (2R(sin A + sin C))/(2R sin B)` `= (2 sin ((A+C)/(2)) cos((A - C)/(2)))/(sin B)` `= (2 sin 60^(@))/(sin 60^(@)) cos ((A - C)/(2))` `= 2 cos ((A - C)/(2))` |
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