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In a triangular field having sides 30 m, 72 m and 78 m, the length of the altitude to the side measuring 72 m is plz answer with full explanation |
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Answer» a TRIANGULAR FIELD having sides 30M 72m 78 ms = (30 + 72 + 78)/2 = 90Area of Triangular Field = √90 (90-30)(90-72)(90-78)= √90 * 60 * 18 * 12= √30 * 3 * 30 * 2 * 6 * 3 * 6 * 2= √ ( 30 * 3 * 2 * 6)²= 1080 m²Area of Triangle = (1/2) * 72 * (length of the altitude to the SIDE measuring 72m)=> (length of the altitude to the side measuring 72m) = 1080 * 2/72= 1080/36= 30 mlength of the altitude to the side measuring 72m = 30 mStep-by-step explanation: |
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