In a tyre of "Ferrari" car of Mr. Obama, a tube having a volume of 12.3 litres is filled with air at a pressure of 4 atm at 300 K.Due to travelling, the temperature of the tube and air inside it raised to 360 K and pressure reduced to 3.6 atm in 20 minutes. If the porosity (number of pores per unit area) of the tube material is 5xx10^3 pores/cm^2 and each pore can transfer air from inside to outside of the tube with the rate of 6.023xx10^8 molecules per minute.Calculate the total surface area (m^2) of the tube.(R=0.082 Lt-atm/mole-K) Give your answer divide by 100.

In a tyre of "Ferrari" car of Mr. Obama, a tube having a volume of 12.

1.	In a tyre of "Ferrari" car of Mr. Obama, a tube having a volume of 12.3 litres is filled with air at a pressure of 4 atm at 300 K.Due to travelling, the temperature of the tube and air inside it raised to 360 K and pressure reduced to 3.6 atm in 20 minutes. If the porosity (number of pores per unit area) of the tube material is 5xx10^3 pores/cm^2 and each pore can transfer air from inside to outside of the tube with the rate of 6.023xx10^8 molecules per minute.Calculate the total surface area (m^2) of the tube.(R=0.082 Lt-atm/mole-K) Give your answer divide by 100.
Answer» Solution :Initial MOLES of air inside the tube `=(4xx12.3)/(0.082xx300)=2` moles of air after 20 minutes`=(3.6xx12.3)/(0.082xx360)=1.5` `:.` moles of air leaked in 20 minutes =2-1.5=0.5 `:.` MOLECULES of air leaked in 20 minutes `=0.5 N_A` Let the total surface AREA of tube =`A cm^2` Total molecules ESCAPED in 20 minutes`=(5xx10^6)A xx 6.023xx10^(8)xx20=0.5 N_A` `:. A=(0.5xx6.023xx10^23)/(5xx10^5xx6.023xx10^8xx20)=5xx10^7 cm^2 =5000 m^2`