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In a uranium ore the ratio of U^(238) nuclei to Pb^(206) nuclei is eta= 2.8. Evaluate the age of the ore, assuming all the lead Pb^(206) to be final decay product of the uranium series. The half-life of U^(238) nuclei is 4.5.10^(9) years |
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Answer» Solution :What this implies is that in the time since the ORE was formed, `(ETA)/(1+ eta)U^(238)` nuclei have remained undecayed. Thus `(eta)/(1_eta)= e^(-txx(IN2)/(T_(1//2))` or `t= T_(1/2)(In (1+eta))/((eta)/(In2))` SUBSTITUTING `T_(1/2)= 4.5xx10^(9)years, eta= 2.8` we GET `t=1.98xx10^(9)`years. |
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