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In a Young's double-slit experiment fringes are obtained on a screen placed at certain distance away from the slits. If the screen is moved by 5 cm towards the slit, the fringe width changes by 30mum. Given that the slits are 1 mm apart. Calculate the wavelength of the light red. |
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Answer» Solution :Here `d=1mm=1xx10^(-3)m,` CHANGE in distance of screen from the slits `DELTAD=5cm=5XX10^(-2)m` and change in fringe width `Deltabeta=mum=30xx10^(-6)m`. From the relation `beta=(lamdaD)/(d)`, we have `Deltabeta=(lamdaDeltaD)/(d)` `implies LAMDA=(dDeltabeta)/(DeltaD)=((1xx10^(-3))xx(30xx10^(-6)))/((5xx10^(-2)))=6xx10^(-7)m=600nm` |
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