1.

In a Young's double slit experiment, the angular width of a fringe formed on distance screen is 0.1^(@).The wvae length of light find spacing between the slit.

Answer»

`3.4 xx 10^(-6) m`
`4.3 xx 10^(-4) m`
`4.3 xx 10^(-6) m`
`3.4 xx 10^(-4) m`

Solution :Using the relation , `theta = (beta)/(D)` and putting `beta = (D LAMBDA)/(d)`, we get `theta = (Dlambda)/(DD) = (lambda)/(d)`
or `d = (6000 xx 10^(-10))/((pi)/(180) xx 0.1) = (6000 xx 180 xx 10^(-10))/(pi xx 0.1)`
`THEREFORE` Spacing between `d = 3.44 xx 10^(-4) m`. Angular fringe width is independent of the distance between screen and PLANE of slits i.e. D.


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