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In a Young's double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 away. The distance between the central bright fringe and the fourth bright fringe in measured to be 1.2 cm. determine the wavelength of light used in the experiment. |
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Answer» Solution :Here `N=4,d=0.28mm=2.8xx10^(-4)m,D=1.4mand x=1.2cm=1.2xx10^(-2)m`. For BRIGHT fringe `x_(n)=(nDlamda)/(d)implieslamda=(x_(n)*d)/(nD)=(1.2xx10^(-2)xx2.8xx10^(-4))/(4xx1.4)=6xx10^(-7)m or 600NM`. |
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