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In a Young's double slit experiment, using mono-chromatic light of wavelength lambda, the intensity of light at a point on the screen where the path defference is lambda is k units. Find the intensity at a point where the path difference is lambda//3. |
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Answer» Solution : A PATH difference of A, corresponds to a phase difference of `2PI` `therefore` intensity , `I=4a^2` or `a^2=I/4` A path difference of `lambda/3`corresponds to a phase difference of `(2pi)/3` `therefore` Intensity =`4xxI/4. cos^2 (2pi)/3` |
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