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In a Young.s double slit experiment wave length of light used is 5000 A and distance between the slits is 2mm, distance from slits is 1m. Find fringe width and also calculate the distance of 7^(th) dark fringe from central birght fringe. |
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Answer» Solution :Given = ` lamda = 5000 xx 10^(-10) m = 5 xx 10^(-7) m` d = ` 2 xx 10^(-3) m , D = 1m ` We knowthat ,fringewidth` BETA = ( lamdaD)/d ` i.e, ` beta = ( 5 xx 10^(-7)xx1 )/( 2 xx 10^(-3)) = 2.5 xx 10^(-4) m ` i.e,`beta = 2.5 xx 10^(-4) m` The distanceof darkfringe ` x_(4) = ((2n+1)beta)/2 ` i.e, Distanceof ` 7^(TH) `darkfringe = ` ((2xx6+1)/2) ( 2.5 xx 10^(-4)) ` n = ` 1.625 xx 10^(-3) m` Hencedistanceof ` 7^(th)` dark fringe = 1.625 mm. |
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